int a[]={3,5,2,6,1,6,43,6,32,1,77};
int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int **p; p=(int**)a;
int a[3][3]={{1,2,3},{4,5},{6}}; int i,
int a[3][5]={{1,2},{6,4},{3,4,5}}; int (*p)[5] = a; 求*(*p+1)
main() { int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int *b; b=a;
{ int a[]={1,2,3,4,5,6}; int*p; p=a; printf("%d\n",*p); prin
int[][]myarray=new int[][]{new int[]{1,2.3},}new int[]{4,5,6
int main() { int a[9] = {1,2,3,4,5,6,7,8,9}; int b[9] = {1,2
#define N 10 main() { int a[N]={1,2,3,4,5,6,7,8,9,10} int i,
C语言 int a;int b; }d[3] ={{1,4},{2,5},{6,7}}; printf("%d\n",d
int a[ ][3]={1,2,3,4,5,6,7,8,9,10,11,12};int*p=a;求 *(*(a+2)+
1.int a[][3]={1,2,3,4,5,6};2.int a[2][]={1,2,3,4,5,6};3.char
有如下程序,int a[10]={1,2,3,4,5,6,7,8,9,10}; int *p=&a[3],b;b=p[5