化简sin²(π+α)sin(3π/2+α)tan(π/2-α)/tan(π-α)cos²(-α-π
化简:[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(
求证:[sin^2(π+α)*cos(π/2-α)+tan(2π-α)*cos(-α)]/-sin^2(-α)+tan(
已知tan(3π+α)=2,求:1、(sinα+cosα)²;2、sinα-cosα/2sinα+cosα
化简:(sin²αtanα+cos²α/tanα+2sinαcosα)sinαcosα
求证:1-2sinαcosα/cos²α-sin²α=tan(π/4-α)
求证(1-2sinαcosα)/(cos²α-sin²α)=tan(π/4-α)
化简sin³(﹣α)cos(2π+α)tan(2π-α)/sin(α-2π)cos(α-3π/2)-tan(π
化简(2cos²α-1)/2tan(π/4+α)sin²(π/4-α)
化简(2cos²α-1)/[2tan(π/4-α)sin²(π/4+α)]
1、已知tan(3π+α)=2,求:(1)(sinα+cosα)²;(2)sinα-cosα/2sinα+co
tanα=2,求sin(π-α)cos(2π-α)sin(-α+ 3π/2)/tan(-α-π)sin(-π-α)的值
1.已知cos(π/6-α)=1/3,求sin(2/3π-α) 2.求证tan^2α-sin^2α=tan^2α-sin