log3 25×log2 27×log5 2^-3=_____
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
log2^25*log3^2倍根号2*log5^9=
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
(log3^4+log5^2)(log2^9+log2^根号3)
我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log
log2^5*log3^2倍根号2*log5^9=
2log5(25)-3log2(64)=?
求值 3^2-log3(2)= log7(log5(log2(32)))=?
log2 25*log3 4 *log5 9
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+
计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
log2(3)+log3(5)+log3(2)=?