等差数列An,Bn的前n项和分别为Sn,Tn且Sn除以Tn等于(3n-1)/(2n+3),求a8除以b8的值
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等差数列An,Bn的前n项和分别为Sn,Tn且Sn除以Tn等于(3n-1)/(2n+3),求a8除以b8的值
a8/b8=2*a8 / 2*b8=(a1+a15)/(b1+b15)=S15/T15=29/33
a8/b8=2*a8 / 2*b8=(a1+a15)/(b1+b15)=S15/T15=29/33
![等差数列An,Bn的前n项和分别为Sn,Tn且Sn除以Tn等于(3n-1)/(2n+3),求a8除以b8的值](/uploads/image/z/19521768-48-8.jpg?t=%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97An%2CBn%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E5%88%86%E5%88%AB%E4%B8%BASn%2CTn%E4%B8%94Sn%E9%99%A4%E4%BB%A5Tn%E7%AD%89%E4%BA%8E%283n-1%29%2F%282n%2B3%29%2C%E6%B1%82a8%E9%99%A4%E4%BB%A5b8%E7%9A%84%E5%80%BC)
an= a1+(n-1)d1
Sn=a1+a2+..+an = n[2a1+(n-1)d1]/2
bn= b1+(n-1)d2
Tn=b1+b2+..+bn=n[2b1+(n-1)d2]/2
Sn/Tn=[2a1+(n-1)d1]/[2b1+(n-1)d2]= (3n-1)/(2n+3)
put n=15
[2a1+14d1]/[2b1+14d2]=44/33
(a1+7d1)/(b1+7d2)=4/3
a8/b8=4/3
Sn=a1+a2+..+an = n[2a1+(n-1)d1]/2
bn= b1+(n-1)d2
Tn=b1+b2+..+bn=n[2b1+(n-1)d2]/2
Sn/Tn=[2a1+(n-1)d1]/[2b1+(n-1)d2]= (3n-1)/(2n+3)
put n=15
[2a1+14d1]/[2b1+14d2]=44/33
(a1+7d1)/(b1+7d2)=4/3
a8/b8=4/3
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