弹性力学习题求解
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/06/25 02:13:40
弹性力学习题求解
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1)
由物理方程
εx=1/E/[δx-μ(δy+δz)]
εy=1/E/[δy-μ(δx+δz)]
εz=1/E/[δz-μ(δx+δy)]
又 εz=0
→ εz=1/E/[δz-μ(δx+δy)]=0
→ δz-μ(δx+δy)=0
→ δz=μ(δx+δy)
→ δz=0.3(35+25)N/mm^2
→ δz=20N/mm^2
εx=1/E/[δx-μ(δy+δz)]
=[1/(2.0*10^5N/mm^2)][35-0.3(25+20)]N/mm^2
=10.75*10^-5
同理 εy=4.25*10^-5
2)
εx=ðu/ðx=0+a1+0+0=a1
γyz=ðw/ðy+ðv/ðz=(0+0+c2+0)+(0+0+0+b3)=c2+b3
同理:
→εy=b2
→εz=c3
→γzx=a3+c1
→γxy=b1+a2
错了请多指教
由物理方程
εx=1/E/[δx-μ(δy+δz)]
εy=1/E/[δy-μ(δx+δz)]
εz=1/E/[δz-μ(δx+δy)]
又 εz=0
→ εz=1/E/[δz-μ(δx+δy)]=0
→ δz-μ(δx+δy)=0
→ δz=μ(δx+δy)
→ δz=0.3(35+25)N/mm^2
→ δz=20N/mm^2
εx=1/E/[δx-μ(δy+δz)]
=[1/(2.0*10^5N/mm^2)][35-0.3(25+20)]N/mm^2
=10.75*10^-5
同理 εy=4.25*10^-5
2)
εx=ðu/ðx=0+a1+0+0=a1
γyz=ðw/ðy+ðv/ðz=(0+0+c2+0)+(0+0+0+b3)=c2+b3
同理:
→εy=b2
→εz=c3
→γzx=a3+c1
→γxy=b1+a2
错了请多指教