因式分解:x²y-y²z+z²x-x²z+y²x+z²y-2
25(x-y)²-10(y-z)+1因式分解
若x-y=6,xy=-8,求代数式(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)的值
因式分解x²-y²-z²+2xy
因式分解x²-y²-z²+2yz
(x-3y+2z)²=
已知x²+y²+z²-2x+4y-6z+14=0,求x+y-z/x+y+z的值
已知x,y,z满足x+y+2z=1,x²+y²+6z+1.5=0,求x,y,z的值
已知x-y=2,y-z=2,x+z=14,求x²-z²的值
已知x-y=2,y-z=2,x+z=14,求x²-z²的值.
已知x+y+z=0,求(y²+z²-x²)分之1+(z²+x²-y
x³+y³+z³-3xyz为什么等于(x+y+z)(x²+y²+z
x≠y≠z,x+y分之一=y+z分之一=z+x分之一,求x²y²z²