-5log9(4)+log3(32/9)-(1/64)^(-2/3),怎么化简,要步骤谢谢.
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
-5log9为底4的对数+log3为底(32/9)的对数-5^(log5为底3的对数)-(1/64)^(-2/3)
[log2(3)+log4(9)][log3(4)+log9(2)]等于
log3 5-log3 15+1/2log9 27 的值
(log4 3+log8 3)(log3 2+log9 2)-log1/2 32^1/3+5^(log25 9)
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))
(log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程
由换底公式怎么得到log9(x+5)=log3[2(x+5)]=1/2log3(x+5)
log 243÷log9 =log3^5÷log3^2 =log3^5-log3^2 然后怎么写
(log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
(log3^2 + log9^4)×(log4^3 + log8^3)