1.sin(2x+π/4)怎么变到→sin(5x+π/4)

1.已知sin(π/6-x)=1/4,sin(π/6+2x)=? 已知sin(π/2-x)+sin(π-x)/cos(-x)+sin(2π-x)=2009,则tan(x+5π/4)等于? Sin^x怎么变化成 1-cos(2x) /2 已知函数fx=（1+1/tanx）sin^x-2sin（x+π/4)sin（x-π/4） y=sin(π/4+x/2)sin(π/4-x/2) =sin(π/4+x/2)sin[π/2-(π/4+x/2)] 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 s = 2*sin(x)-sin(2*x)+2/3*sin(3*x)-1/2*sin(4*x)+2/5*sin(5*x) 已知sin(x+π/6)=1/4,则sin(7π+x)+sin^2(5π/6-x)的值 已知函数f(x)=sin^2 x+2根号3sinxcosx+sin(x+π/4)sin(x-π/4),x属于R,求f(x 已知f(x)=cos^2x+sinxcosx g(x)=2sin(x+π/4)sin(x-π/4) 已知函数f(1+cotx)sinx^2-2sin(x+π/4)sin(x-π/4) 化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π