作业帮 > 数学 > 作业

设等差数列{an}的前n项和为Sn,已知(a5-1)3+2009(a5-1)=1,(a2005-1)3+2009(a20

来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/05/15 13:04:25
设等差数列{an}的前n项和为Sn,已知(a5-1)3+2009(a5-1)=1,(a2005-1)3+2009(a2005-1)=-1,则下列结论中正确的是(  )
A. S2009=2009,a2005<a5
B. S2009=2009,a2005>a5
C. S2009=-2009,a2005≤a5
D. S2009=-2009,a2005≥a5
设等差数列{an}的前n项和为Sn,已知(a5-1)3+2009(a5-1)=1,(a2005-1)3+2009(a20
∵等差数列{an}的前n项和为Sn,(a5-1)3+2009(a5-1)=1,
∴(a5-1)[(a5−1)2+2009]=1,
∵(a5−1)2+2009>0,
∴a5-1>0,即:a5>1.
∵(a2005-1)3+2009(a2005-1)=-1,
∴(a2005-1)[(a2005−1)2+2009]=-1,
∵(a2005−1)2+2009>0,
∴a2005-1<0,即:a2005<1.
∴a2005<a5
据上可知应选A.
故选:A.