x/(y+z)=y/(x+z)=z/(x+y)

来源：学生作业帮编辑：百度作业网作业帮分类：数学作业时间：2024/05/14 13:17:03

x/(y+z)=y/(x+z)=z/(x+y)
x/(y+z)=y/(x+z)=z/(x+y)=(x+y+z)/[(x+z)+(x+y)+(y+z)]=1/2
y/(x+z)=z/(x+y)=（y-z）/【（x+z）-（x+y）】=-1
我知道这是两种情况做法一是x+y+z≠0
做法二是x+y+z=0
我的疑问是做法二在证明中那里用到了x+y+z=0

x+y+z=0
所以第一种分母为0,不能用
所以此时就换了一种方法
再问：我知道第一种再约分过程中若为0，无法约
但做法二在证明中哪里用到了x+y+z=0
再答：我说了，不是直接用
采纳吧

(x+y-z)(x-y+z)= X+Y+Z=? f(x,y,z,w)=x*(x+y)*(x+y+z)*(x+y+z+w) x y z x+y--- = --- = ---- ----y+Z z+x x+y ,求 z 的值 .求 x+y---- 已知x+y-z/z=x-y+z/y=-x+y+z/x,且xyz不等于0,求分式[(x+y)(x+z)(y+z)]/xyz 若z分之x+y+z=y分之x-y+z=x分之-x+y+z,求xyz分之(x+y)(y+z)(z+x) y+z÷x=Z+X÷y=X+Y÷z,X+Y+Z不等0求X+Y-Z÷X+Y+z值 (x+y-z)/z=(y+z-x)/x=(z+x-y)/y 求(x+y)(y+z)(z+x)/xyz x分之y+z=y分之z+x=z分之x+y(x+y+z不等于0）,求x+y+z分之x+y-z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知：(x+y-z)/z=(x-y+z)/y+(y+z-x)/x,且xyz≠0,求代数式[(x+y)(y+z)(x+z) 1.设有比例式：x/(y+z)=y/(x+z)=z/(x+y),有比例性质,得x/(y+z)=y/(x+z)=z/(x+