编写程序,求30以内的所有素数之和,用do while做

#include#include#include#defineMAX_NUMBER500/*本程序默认求500以内的亲密数可以输入参数,求亲密数的范围：假定程序名为qinmi.exeqinmi.exe

floatfun(intm){    inti,j,count,iszishu;    floatsum; &

#include#includemain(){intx,k,flag,n=0;for(x=100;x再问：谢谢】

#includemain(){inti,k;for(i=1000;i

publicclassTest{publicstaticvoidmain(String[]args){intsum=0;inti=2;while(i

哈?拿着mathematica却要用原始素数定义来解题?锈到了吗?list=Select[Range@1000,PrimeQ]Total@list得到的答案是：(*{2,3,5,7,11,13,17,

cleart=1;fori=1:100forj=1:iif(round(i/j)==(i/j)&j~=1&j~=i)breakendendifj==is(t)=i;t=t+1;%disp(['素数:'

k=sqrt(i);改成k=sqrt(i*1.0)看不懂你这个程序,一会帮你重新写一个#include#defineMAX30voidmain(){intn=1,s=0,i,j,k;for(i=1;i

#include#includeintis_prime(intn);intmain(){inti,sum=0;for(i=2;i

#includeusingnamespacestd;intmain(){inta,b,c,count=0;ofstreamofile;//定义输出文件ofile.open("myfile.txt");

clears=0fori=1to200step2s=s+iendfor"200以内所有奇数的和:",s

fori=200to500flag=1forj=2toi+1ifimodj=0thenflag=0:exitfornextjifflag=1thens=s+i:prints,i

刚好在做C++,顺便帮你做下,#includemain(){inta,i,sum=0;printf("素数:\n");for(a=1;a

很简单马上好楼下学我的走远点11313113713917317919119319719923323929331131331737337941943143343947959359961361761967

#include#includeboolisPrime(intnum){if(num!=2&&num%2==0)//除2以外的偶数都不是素数{returnfalse;}for(inti=3;i

你写的其实不错啊!只是在最后一个if语句出了问题!#include"stdio.h"#include"math.h"intss(intx){intk;for(k=2;k

#includeintmain(){inti,j,n,k=0;scanf("%d",&n);for(i=2;i

#include#includevoidmain(){inti,j,sum=0,s;for(i=3;i{s=sqrt((double)i);for(j=2;j{if(i%j==0)break;}if(

clearsettalkoffs=0fora=2to100flag=0b=2dowhile

500以内的所有的素数23571113171923293137414347535961677173798389971011031071091131271311371391491511571631671