m-m分子1=3,则m^2-搜答案-百度作业网

m^2+m=1m^3+2m^2+2004=m(m^2+m)+m^2+2004=m+m^2+2004=2005

原式=9-m2+m2-6m-7=-6m+2=-6*1/2+2=-1

2m^2-3m+m^（-2）=m^2+m^（-2）+m^2-3m=（m-1/m）^2+m^2-3m+2∵m²-3m-1=0显然m≠0∴m²-3m=1m-3-1/m=0即m-1/m=

(m+1/m)=(m-1/m)+4=3*3+4=13m-1/m=（m-1/m）(m+1/m)=3√13

m*m-3m+1=0移项得m*m=3m-1可得m=3-1/m∴m+1/m=3两边平方,得m*m+1/m*m=9∵2m*m+2\m*m=2(m*m+1/m*m)代入,得2m*m+2\m*m=2×9=18

错了,是m³+2m²+3m²+m=1原式=m³+m²+m²+3=m(m²+m)+m²+3=m+m²+3=1+3

m³+2m²=m³+m²+m²=m(m²+m)+m²=m+m²=1所以原式=2010

(m+3m+5m+7m+.+2009m)-(2m+4m+6m+.+2008m)=(1+3+5+7+.+2009)m-(2+4+6+.+2008)m=【(1+2009)×1005÷2-（2+2008）×

2m(3m-5)+3m(1-2m)=146m^2-10m+3m-6m^2=14-7m=14m=-2

括号里面乘出来：M-M^3+M^3-2M+2012>=0,M-2M+2012>=0,得：M

m^2+m-1=0m^2+m=1m^3+2m^2+1=m(m^2+m)+m^2+1=m+m^2+1=1+1=2

m-2m-3m+4m-5m-6m+7m.2004m=(1-2-3+4-5-6+7-8-9+...2002-2003-2004)m=(-4-7-10-..-2005)m=-(4+7+10+..+2005

∵复数z为纯虚数∴m(m+2)÷(m-1)=0,且m^2+2m-3≠0解得m=-2或m=0

(1m+3m+5m+...+2009m)-(2m+4m+6m+...+2008m)=1m+3m+5m+...+2009m-2m-4m-6m-...-2008m=1m+(3m-2m)+(5m-4m)+.

（m2013m）*1007/2－（2m2012m）*1006/2=1007m

=m+(3m-2m)+(5m-4m)+……+(2015m-2014m)=m+1007m=1008m

4.5*5=4.5+(4.5+1)+(4.5+2)+(4.5+3)+(4.5+4)+4.5+5)=4.5x6+1+2+3+4+5=27+15=42m*8=37.8m*n=m+(m+1)+(m+2)+(

由(2x+1)/2=6x-2得：x=0.5所以(x-m)/2=m/(x+3)的解为1/0.5=2所以(2-m)/2=m/5m=10/7

(m)(m)-2m=1两边乘22(m)(m)-4m=2所以2(m)(m)-4m+2008=2+2008=2010