A为3阶矩阵,a1,a2,a3为3维列向量组,（Aa1,Aa2,Aa3）为什么根据分块矩阵乘法可分为A（a1,a2,a3

A为3阶矩阵,a1,a2,a3为3维列向量组,（Aa1,Aa2,Aa3）为什么根据分块矩阵乘法可分为A（a1,a2,a3 设A为三阶矩阵,三维列向量a1,a2,a3线性无关,且满足Aa1=2a1+a2+a3,Aa2=2a2,Aa3=-a2+a 设A为n阶矩阵,a1,a2,a3是n维列向量,且a1不等于0,Aa1=a1,Aa2=a1+a2,A 线性代数证明题A为n阶矩阵,a1,a2,a3是n维向量,且a1不等于0,Aa1=a1,Aa2=a1+a2,Aa3=a2+ 设三维列向量a1,a2,a3线性无关,A是三阶矩阵,且有Aa1=a1+2a2+3a3,Aa2=2a2+3a3,Aa3=3 已知A是n阶方阵,a1,a2,a3为n维列向量,且a1≠0,Aa1=a1,Aa2=a1+a2,Aa3= a2+a3,求证 设a1,a2为n维列向量,A为n阶正交矩阵,证明[Aa1,Aa2]=[a1,a2] 已知n维向量a1,a2,a3,a4,a5线性无关,A是n阶可逆矩阵,证明Aa1,Aa2,Aa3,Aa4,Aa5线 设三维列向量a1,a2,a3线性无关,A是三阶矩阵,且有Aa1=2a1+4a2+6a3,Aa2=4a2+6a3,Aa3= 设a1,a2为n维列向量,A为n阶正交矩阵,证明:(1)[Aa1,Aa2]=[a1,a2] (2){Aa1}={a1} 设A是3阶矩阵,a1a2a3是三维线性无关的列向量,且Aa1=4a1-4a2+3a3 Aa2=负6a1-a2+a3 Aa 设a1,a2,a3均为3维列向量,记矩阵A=(a1,a2,a3)B=（a1+a2+a3,a1+2a2+2a3,a1+3a