select * from tab_a inner join tab_b on tab_a.col1 = tab_b.c

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select * from tab_a inner join tab_b on tab_a.col1 = tab_b.col1 inner join tab_c on tab_b.col1 = ta
select * from
tab_a inner join tab_b on
tab_a.col1 = tab_b.col1
inner join tab_c on
tab_b.col1 = tab_c.col1
and tab_b.col2 = tab_c.col2;
其中的co|1、co|2是指什么,tab_a 、 tab_b 、tab_c是表名对吧,on tab_b.col1 = tab_c.col1 and tab_b.col2 = tab_c.col2;是指什么

co|1、co|2 表的列1列2的简写； on tab_b.col1 = tab_c.col1 and tab_b.col2 = tab_c.col2是指join的字段

select * from tab_a inner join tab_b on tab_a.col1 = tab_b.c $sql_notice = "select * from $t_article art inner join $t_ar select * from userinfo a inner join emp b on a.userinfoid li select ···fromA join B on·····和select····from A inner join B select * from a,b与select * from a inner join b 的取数方式和执行效率有什么 select s.name,s.course,s.grade from student as s inner join sql 中 select * from A left join B on A.id=B.id where A.id=?如 sql函数,select count(A.abc) as sum from A left join B on A.id= sql根据已有的表建新表：create table tab_new as select col1,col2… from sql="select P.*,T.name as Typename from tb_function P inner inner join 与 =区别 ORACLE 中 select B.f from a A left join b B on A.e=B.e 如果B.f为