max=a>b?(a>c?a:c):(b>c?b:c); mid=a>b?(ab?(a>c?a:c):(b>c?b:c)

max=a>b?(a>c?a:c):(b>c?b:c); mid=a>b?(ab?(a>c?a:c):(b>c?b:c) C语言中,max=(a>((b>c)?b:c)?a:(b>c:b:c)); (a-b-c)(b+c-a)(c-a+b)= a>b>c,a+b+c=0,求证c/(a-c)>c/(b-c) Max=((a>b?a:b)>c)?(a>b?a:b):c; 行列式证明|b+c c+a a+b| | a b c||a+b b+c c+a| = 2 |c a b||c+a a+b 已知(b+c)/(a)=(c+a)/(b)=(a+b)/(c) 求(a+b)/(c) 证明 +(a-b)(b-c)(c-a)/(a+b)(b+c)(c+a)=0 (a-b)b+c(b-a)=c(c-a)+b(a-c)? a+b+c=0,abc求a(b+c)+b(a+c)+c(a+b) [(a-b)(b-c)(c-a)]÷[(a-c)(c-b)(b-a)]= 输入a,b,c,计算m.已知 m=max（a,b,c)/max(a+b,b,c)*max(a,b,b+c) 将求三个数的