根号3 cosx+sinx=-6/5,则sin(π/3-x)=
根号3 cosx+sinx=-6/5,则sin(π/3-x)=
设f(x)=2cosx.sin(x+π/3)-根号3 sin平方x+sinx.cosx
已知函数f(x)=2cosx*sin(x+π/3)-根号3sin^2x+sinx*cosx
化简(根号3)/2sinx+1/2cosx=sin(x+π/6),
sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x
证明:Sinx+(根号3)*Cosx=2Sin(x+π/3)
求证sinx-cosx=根号2sin(x-π/4)
已知(sinx+cosx)/(sinx-cosx)=3,求tanx,2sin²x+(sinx-cosx)&su
Y=2COSX·sin(X+pai/3)-根号3sin平方X+sinX·cosX
若根号3sinx-cosx=sinx+根号3cosx且X属于(0,π),则X=
a=(2cosx,sinx),b=(sin(x+3分之π),cosx-根号下3sinx),f(x)=a×b.求函数f(x
已知a向量=(2cosx,sinx),b向量=(sin(x+π/3),cosx-根号3sinx) f(x)=a向量×b向