初二下学期分式的计算······很急拜托了···
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/06/14 02:17:08
初二下学期分式的计算······很急拜托了···
(1)x-2分之3,6-3x分之2 通分 (2)(x+1)(x-4)分之1,(x-4)的平方分之2 通分 (3)3(y-1)分之x,6-3x分之2 通分 ((x-1)(x-2)分之1,x平方-2x+1分之2 通分
(1)x-2分之3,6-3x分之2 通分 (2)(x+1)(x-4)分之1,(x-4)的平方分之2 通分 (3)3(y-1)分之x,6-3x分之2 通分 ((x-1)(x-2)分之1,x平方-2x+1分之2 通分
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1、3/(X-2)+2/(6-3X)=3/(X-2)-2/[3(X-2)]=9/[3(X-2)]-2/[3(X-2)]
2、(x+1)(x-4)分之1+(x-4)的平方分之2
=1/(X+1)(X-4)+2/(X-4)²=(x-4)/(x+1)(x-4)²+(x+1)/(x+1)(x-4)²
(3)3(y-1)分之x+6-3x分之2
=x/3(y-1)-2/[3(x-2)]=x(x-2)/[3(y-1)(x-2)]-2(y-1)/[3(y-1)(x-2)]
4) (x-1)(x-2)分之1+x平方-2x+1分之2
=1/(x-1)(x-2)+2/(x-1)²=(x-2)/(x-1)²(x-2)+2(x-2)/(x-1)²(x-2)
2、(x+1)(x-4)分之1+(x-4)的平方分之2
=1/(X+1)(X-4)+2/(X-4)²=(x-4)/(x+1)(x-4)²+(x+1)/(x+1)(x-4)²
(3)3(y-1)分之x+6-3x分之2
=x/3(y-1)-2/[3(x-2)]=x(x-2)/[3(y-1)(x-2)]-2(y-1)/[3(y-1)(x-2)]
4) (x-1)(x-2)分之1+x平方-2x+1分之2
=1/(x-1)(x-2)+2/(x-1)²=(x-2)/(x-1)²(x-2)+2(x-2)/(x-1)²(x-2)