log2(12)-log4(9)的值是
log2(12)-log4(9)的值是
算式log2^12-log4^9的值
(log2底5+log4底0.2)(log4底2+log25底0.4)的值是
log2^x=log4^9
log4 243 - log8 729=?log4 12 - log2 6=?
对数问题 log2^x=log4^9
若log3(7)·log2(9)·log49(a)=log4(1/2),则a的值等于
log4(12)与log8(27)的差和log4(27)与log2(6)的差的比值为
log2(log3(log4的对数a))=log3(log4(log2的对数b))则a/b的值为?
log2 3 · log3 4 ·log4 5 ·log5 2 前面的是底数
化简:(log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根)
(log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根