若Sn=an2+bn(a.b是实数)则数列(an)是等差数列对不对
数列{an}的前n项和sn=an2 +bn(a,b为常数),试证明{an}是等差数列,并求a1和d.
【高中数学】数列{an}的前N项和为Sn,求证:Sn=an2+bn(a,b∈R)是数列{an}为等差
证明:数列{an}为等差数列的充要条件是数列{an}的前n项和为sn=an²+bn(其中啊a,b为常数)
若数列An的前n项和为Sn=an^2+bn+c,(a,b,c属于正整数)则An为等差数列的充要条件是c=0.
已知数列{an}得前n项和为sn=an^2+bn(a,b为常数且a不等于0)求证数列{an}是等差数列
已知数列an是等差数列,且bn=an+a(n+1).求证数列bn是等差数列.
已知数列{An}是等差数列,且Bn=An+A(n+1).求证数列{Bn}是等差数列
数列{an}的前n项和为Sn,存在常数A,B,C,使得an+Sn=An2+Bn+C对任意正整数n都成立.若数列{an}为
试证明:数列{an}为等差数列的充要条件是其前n项和Sn=an^2+bn(常数a,b∈R) 感激.
已知数列{an}是等差数列,且bn=an+a(n-1),求证bn也是等差数列
在正整数数列{an}中,Sn=0.125(an+2)^2.(1)求证{an}是等差数列(2)若bn=0.5an-30,求
已知数列{an}的前n项和sn满足sn=an^2+bn,求证{an}是等差数列