设f(x)具有二阶导数f''(x),证明f''(x)=lim(f(x+h)-2f(x)+f(x-h))/h^2
设f(x)具有二阶导数f''(x),证明f''(x)=lim(f(x+h)-2f(x)+f(x-h))/h^2
设f(X)在x=x0处具有二阶导数f''(x0),试证:lim(h→0)(f(x0+h)-2f(x0)+f(x0-h))
若f(x)有二阶导数,证明f''(x)=lim(h→0)f(x+h)-2f(x)+f(x-h)/h^2.
设函数f(x)具有二阶导数,且f(x)二阶倒大于0,证明:f(a+h)+f(a-h)≥2f(a)
f(x)具有连续的二阶导数f,(x),证明f,(x)=[f(x+h)+f(x-h)-2f(x)]/h^2 (h趋于0)
设函数f(x)在x=Xo处具有二阶导数f''(Xo),证明{f(Xo+h)+f(Xo-h)-2f(Xo)}/h^2的极限
导数极限形式的证明1)f'(x0)=lim(x→x0)[f(x)-f(x0)]/(x-x0) 2)f'(x)=lim(h
设f(x)在x=x0的临近有连续的2阶导数,证明:lim(h趋近0)f(x0+h)+f(x0-h)-2f(x0)/h^2
设函数f(x)在x=x0处可导,则lim(h>0)[f(x0)-f(x0-2h)]/h
设f'(x) = 3^(1/2) ,求 lim(h→0) [f(x+mh) - f(x - nh)] / h ,(m ,
设f(x)在x=a处可导,f'(x)=b 求极限lim(h-0) f(a-h)-f(a+2h)/ h
关于微分的假设f( x )的二阶导数存在证明f(x)的二阶导数等于x趋近于0时候[f(x+h)-f(x-h)-2f(x)