百度作业网解下列奥数题：答对者给予80分奖励!加油!
来源：学生作业帮 编辑：百度作业网作业帮 分类：英语作业 时间：2024/06/24 15:03:21
解下列奥数题：答对者给予80分奖励!加油!
1.某次猜谜语比赛,谜语按难易分两类,每人可以猜三条.每猜对一题较难的谜语得3分,每猜对一条较容易的谜语得1分.如果有8人得1分,7人得2分,6人得3分,5人得4分,4人得5分.恰好猜对两题谜语的有几人?
2.A certain make of pen（一种牌子的钢笔）was priced 50 cents in the store but found few buyers. Then the store had reduced the price (减价,降价),the whole remaining stock (存货）was sold for $31.93. What was the retuced price?
3.If r and s are integers,each greater than 1, and if 11（s—1）=13（r—1）,what is the least possible value (最小值)of +s?
1.某次猜谜语比赛,谜语按难易分两类,每人可以猜三条.每猜对一题较难的谜语得3分,每猜对一条较容易的谜语得1分.如果有8人得1分,7人得2分,6人得3分,5人得4分,4人得5分.恰好猜对两题谜语的有几人?
2.A certain make of pen（一种牌子的钢笔）was priced 50 cents in the store but found few buyers. Then the store had reduced the price (减价,降价),the whole remaining stock (存货）was sold for $31.93. What was the retuced price?
3.If r and s are integers,each greater than 1, and if 11（s—1）=13（r—1）,what is the least possible value (最小值)of +s?
1、因为猜对2题的人只有3种情况：A、猜对2条1分题；B、猜对2条3分题；猜对1分、3分题各一题,依题意可知答案为：7+5＝12人
2、将31.93乘以100得3193,3193＝31×103,
即31.93＝31×1.03＝3.1×10.3＝0.31×103,所以降价后的价格可以是：31、1.03、3.1、10.3、0.31、103其中一个
而只有$0.31是小于原价$0.50的,所以降价后的价格是$0.31
3、最后问题问的看不懂,
因为11（s—1）=13（r—1）,且s、r都是大于1的整数,所以s－1的最小整数值是13,所以s的最小值是14,同理,r－1的最小值是11,r的最小值是12
2、将31.93乘以100得3193,3193＝31×103,
即31.93＝31×1.03＝3.1×10.3＝0.31×103,所以降价后的价格可以是：31、1.03、3.1、10.3、0.31、103其中一个
而只有$0.31是小于原价$0.50的,所以降价后的价格是$0.31
3、最后问题问的看不懂,
因为11（s—1）=13（r—1）,且s、r都是大于1的整数,所以s－1的最小整数值是13,所以s的最小值是14,同理,r－1的最小值是11,r的最小值是12