“双线桥”法配平:NaSx+NaBrO3+NaOH----Na2SO4+NaBr+H2O.最后附有说明)
“双线桥”法配平:NaSx+NaBrO3+NaOH----Na2SO4+NaBr+H2O.最后附有说明)
NaSx+NaClO+NaOH-Na2SO4+NaCl+H2O
Br2+2NaOH=NaBr+NaBrO+H2O (或3Br2+6NaOH=5NaBr+NaBrO3+3H2O)
5nabr+nabro3+3h2so4=3br+3na2so4+3h2o 这个反应中电子
此方程式的原理?3Br2+6NaOH→5NaBr+NaBrO3+3H2O
5NaBr+NaBrO3+3H2SO4=3Br2+3Na2SO4+3H2O 氧化剂―― 氧化产物―
5NaBr+NaBrO3+3H2SO4=3Br2+Na2SO4+3H2O中氧化产物和还原产物各是什么?
Br2&NaOH反应,能生成NaBr&NaBrO3吗?
从海水中提取溴的过程中有如下反应:5NaBr+NaBrO3+3H2SO4═3Br2+Na2SO4+3H2O,与该反应在氧
CH3CH2Br+NaOH=H2O △CH3CH2OH+NaBr
已知 H2SO4+2NaOH=Na2SO4+2H2O(Na2SO4中性,NaOH碱性)若稀H2SO4和NaOH溶液质量和
Ag2SO4与NaOH反映后生成AgOH(>Ag2O+H2O)+Na2SO4,如何除去Na2SO4?