x+y+z=2 4x+2y+z=4 2x+3y+z=1
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x+y+z=2 4x+2y+z=4 2x+3y+z=1
(x-2y+z)/9=(2x+y+3z)/10=-(3x+2y-4z)/3=1 连等,求x,y,z,
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
2x+3y+z=1 x+y+z=-2 3x-2y-z=-4 求x、y、z
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
{5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-
1.已知x,y,z满足2│x-y│+(根号2y-z)+z平方-z+(1/4)=0,求x,y,z值.
{x+y+z=4 {2y+z=0 {3x+2y-4z=-1
若x-2y+4z=1,x+3y-7z=0,则y:z=?
已知x:y:z=4:5:7,求:(1)2x+3y+z/5z; (2)x+y/y+z.