求问一道电路原理题目,关于诺顿定理
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求问一道电路原理题目,关于诺顿定理
Us、R1、Is 合并为一个电压源 Us1:
Us1 = Us + 1 * 20 = 30 V
受控电流源、R3 转换为电压源:
Us2 = GU * 20 = 0.75U
求输出端短路电流 Isc :
Isc = (30 - uU)/ (R1+R2) + (Us2 - uU) / R3
Isc =0.75 A
求开路电压 Usc:
I = (30 - Us2) / (R1+R2+R3)
= (30 - 0.75U) / 60
= 0.5 - 0.0125 * 20 * I
I = 0.4 A
Usc = 30 - I (R1+R2) - uU
= 30 - 0.4 * 40 - 0.5 * 0.4 * 20
= 10 V
求内阻 R0:
R0 = Usc / Isc
= 10 / 0.75
= 1.333Ω
诺顿等效电路为 0.75 A 电流源并联 1.333 Ω电阻.
Us1 = Us + 1 * 20 = 30 V
受控电流源、R3 转换为电压源:
Us2 = GU * 20 = 0.75U
求输出端短路电流 Isc :
Isc = (30 - uU)/ (R1+R2) + (Us2 - uU) / R3
Isc =0.75 A
求开路电压 Usc:
I = (30 - Us2) / (R1+R2+R3)
= (30 - 0.75U) / 60
= 0.5 - 0.0125 * 20 * I
I = 0.4 A
Usc = 30 - I (R1+R2) - uU
= 30 - 0.4 * 40 - 0.5 * 0.4 * 20
= 10 V
求内阻 R0:
R0 = Usc / Isc
= 10 / 0.75
= 1.333Ω
诺顿等效电路为 0.75 A 电流源并联 1.333 Ω电阻.