斐波那契数列an满足a1=1,a2=2,求证：任意n为正整数,都有（an+1）^(1/n)≥1+1/((an)^(1/n

斐波那契数列an满足a1=1,a2=2,求证：任意n为正整数,都有（an+1）^(1/n)≥1+1/((an)^(1/n 数列{an}满足an=2an-1+2^n+1(n为正整数,n≥2）,a3=27 (1)求a1,a2的值 数列{an}满足a1+2a2+2^2a3+.+2^n-1an=n/2(n属于正整数）, 数列an满足a1=2,对于任意的n∈正整数集,都有an＞0,且（n+1)an^2+an*an+1(是下标）-n(an+1 数列an=2^(n-1),数列cn满足,对任意正整数c1/a1+c2/a2+...+cn/an=22+（2n-11）/2 在数列{an}中,已知对任意正整数n,有a1+a2+...+an=(2^n)-1那么a1^2+a2^2+..,+an^2 已知数列{an}满足:a1+a2+a3+…+an=n-an 求证{an-1}为等比数列 令bn=(2-n)(an-1)求 已知数列an中,a1=1,a2=0,对任意正整数n,m（n>m）满足（an）²-（am）²=(an- 对任意正整数n,数列an均满足a1+2a2+3a3+……+nan=n(n+1)(n+2） 设数列an满足a1=a2=1,a3=2,且对正整数n都有an·an+1·an+2·an+3=an+an+1+an+2+a 在数列{an}中,a1=2010,且对任意正整数,都有a(n+2)=a(n+1)-an,则a2+a3+a4+……+a20 一直数列{An}满足A1=1/2,A1+A2+…+An=n^2An