[(1-√3i)^5-(1+√3i)^4]/[i*(-1+i^8)*(1/2+1/2i)]的答案是2√3-4i,
[(1-√3i)^5-(1+√3i)^4]/[i*(-1+i^8)*(1/2+1/2i)]的答案是2√3-4i,
i^0!+i^1!+i^2!+i^3!+...+i^100!
复数除法 计算1+i/1-i,1/i,7+i/3+4i (-1+i)(2+i)/-i
(-1+√3i)^3/(1+i)^6+(-2+i)/(1+2i)的值是
1+i-2i^2+3i^3-4i^4+5i^5
计算(1+2i)+(2-3i)+(3+4i)+(4-5i)+...+(2008-2009i)
复数的计算1.i* i^2 * i^3 *.* i^20082.(1+i)^15+(1-i)^15/(1+i)^14-(
计算(i^2+i)+|i|+(1+i)
(1)i/1+i(2)2/(1+i)^2(3)(3-i)/(3+4i)(4)(3-4i)(1+2i)/2i
计算((-1+√3i)^3/(1+i)^6)+((-2+i)/(1+2i))
((-1+√3i)^3/(1+i)^6)-((-2+i)/(1+2i))过程怎么写
计算(1-2i)-(2-3i)+(3-4i)-(4-5i)=