若0<θ<π/2,化简(sinθ/1-cosθ)*根号tanθ-sinθ/tanθ+sinθ (大根号,后面都包括)
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若0<θ<π/2,化简(sinθ/1-cosθ)*根号tanθ-sinθ/tanθ+sinθ (大根号,后面都包括)
![若0<θ<π/2,化简(sinθ/1-cosθ)*根号tanθ-sinθ/tanθ+sinθ (大根号,后面都包括)](/uploads/image/z/4162311-63-1.jpg?t=%E8%8B%A50%EF%BC%9C%CE%B8%EF%BC%9C%CF%80%2F2%2C%E5%8C%96%E7%AE%80%EF%BC%88sin%CE%B8%2F1-cos%CE%B8%EF%BC%89%2A%E6%A0%B9%E5%8F%B7tan%CE%B8-sin%CE%B8%2Ftan%CE%B8%2Bsin%CE%B8+%EF%BC%88%E5%A4%A7%E6%A0%B9%E5%8F%B7%2C%E5%90%8E%E9%9D%A2%E9%83%BD%E5%8C%85%E6%8B%AC%EF%BC%89)
[sinθ/(1-cosθ)]•√[(tanθ-sinθ)/(tanθ+sinθ)]
= [sinθ/(1-cosθ)]•√[(tanθ-tanθ•cosθ)/(tanθ+tanθ•cosθ)]
= [sinθ/(1-cosθ)]•√[(1-cosθ)/(1+cosθ)]
= [sinθ/(1-cosθ)]•√[(1-cosθ)²/(1+cosθ)(1-cosθ)]
=[sinθ/(1-cosθ)]•√[(1-cosθ)²/(1-cos²θ)]
=[sinθ/(1-cosθ)]•[(1-cosθ)/sinθ]
=1
= [sinθ/(1-cosθ)]•√[(tanθ-tanθ•cosθ)/(tanθ+tanθ•cosθ)]
= [sinθ/(1-cosθ)]•√[(1-cosθ)/(1+cosθ)]
= [sinθ/(1-cosθ)]•√[(1-cosθ)²/(1+cosθ)(1-cosθ)]
=[sinθ/(1-cosθ)]•√[(1-cosθ)²/(1-cos²θ)]
=[sinθ/(1-cosθ)]•[(1-cosθ)/sinθ]
=1
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