作业帮 > 数学 > 作业

已知x²-x-2xy+y+y²,求代数式½(x²+y²)-xy的值

来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/04/29 13:45:45
已知x²-x-2xy+y+y²,求代数式½(x²+y²)-xy的值
x²-x-2xy+y+y²=2,求代数式½(x²+y²)-xy的值
已知x²-x-2xy+y+y²,求代数式½(x²+y²)-xy的值
已知x²-x-2xy+y+y²=0
x²-2xy+y²-x+y=0
(x-y)²-(x-y)=0
(x-y)(x-y-1)=0
x-y=0 (x-y-1)=0
(1)x-y=0
代数式½(x²+y²)-xy的值
=1/2(x²+y²-2xy)
=1/2(x-y)²
=1/2* 0²
=0
(2)x-y-1=0
x-y=1
代数式½(x²+y²)-xy的值
=1/2(x²+y²-2xy)
=1/2(x-y)²
=1/2* 1²
=1/2
再问: 发漏了不好意思啊是x²-x-2xy+y+y²=2
再答: x²-x-2xy+y+y²=2 x²-2xy+y²-x+y-2=0 (x-y)²-(x-y)-2=0 (x-y-2)(x-y+1)=0 x-y=2 x-y=-1 (1)x-y=2 代数式½(x²+y²)-xy的值 =1/2(x²+y²-2xy) =1/2(x-y)² =1/2* 2² =2 (2)x-y=-1 代数式½(x²+y²)-xy的值 =1/2(x²+y²-2xy) =1/2(x-y)² =1/2* (-1)² =1/2