一道化简题 (x+y)+(2x+1/1×2y)+(3x+1/2×3y)+……+(9x+1/8×9y) 请问该怎么化简.
一道化简题 (x+y)+(2x+1/1×2y)+(3x+1/2×3y)+……+(9x+1/8×9y) 请问该怎么化简.
9y=3x-(x-1),4(x+y)-(2x+4)=8y
1、x(x-y)(x+y)-x(x+y)^2
化简求值:(x+y)+(2x+1/2y)+(3x+1/6y)+.+(9x+1/72y) ,其中x=1,y=-9
化简求值:(7x-2y)(3x-2y-1)-(4x+3y)(9x+6y),其中x=2,y=-1
化简:(x+y)+(2x+y/1*2)+(3x+y/2*3)+...+(9x+y/8*9)
化简(x+y)+(2x+y/1*2)+(3x+y/2*3)+.+(9x+y/8*9)
因式分解 (1)6(x-y)^3-3y(y-x)^2 (2)x(x-y)(a-b)-y(y-x)(
9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y的平方(x-y)(x+1),因式分解
先化简再求值:(x-2y)²-(x+2y)(x-2y)-(x-3y)(x-y).其中x²+9y
(1)(x^2/x)-y-x-y
先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y