5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
已知a-b/2=b-2c/3=3c-a/4.求5a+6b-7c/4a-3b+9c
(a-b)(b-c)(c-a)/(b-a)(a-c)2(c-b)3
{A+2B-3C=4,5A-6B+7C=8}求代数式A:B:C 2A-3C/A+2B
已知a+b/a-b=b+c/2(b-c)=c+a/3(c-a),求证:8a+9b+5c=0
(a+b)/(a-b)=(b+c)/2(b-c)=(c+a)/3(c-a),abc互不相等,证8a+9b+5c=o
化简(2a-b-c)/(a+b)(a-c)+(2b-c-a)/(b-c)(b-a)+(2c-a-b)/(c-b)(c-a
3a-{2c-[6a-(c-b)+c+(a+8b-6)]}.
(a+b-c)(a-b+c)
(a+b-c)^5(a-b-c)^2(c-a-b)^4(c+b-a)^3 计算
若|a|=5,|b|=2,|c|=6且|a+b|=-(a+b),|a+c|=a+c,求a-b+c的值
b/(a+c)=1/2,a/(b+c)=1/5 怎么得出a/(a+b+c)=1/6,b/(a+b+c)=1/3?