(1/3a^ n+2 +2a^n+1) ÷ (-1/3 a ^ n-1 ) 计算
计算:(3a^n+2+6a^n+1-9^n)÷3a^n-1
计算:(6a^n+2-9a^n+1+3a^n-1)÷3a^n-1
(3a^(n+1)+6a^(n+2)-9a^n)/3a^(n-1)是计算
分式 计算:a^(2n+1)-6a^(2n)+9a^(2n-1) / a^(n+1)-4a^n+3a^(n-1)
(2分之3a^n+3 -2a^n+1)÷(-3分之1a^n-1) 计算
(1/3a^ n+2 +2a^n+1) ÷ (-1/3 a ^ n-1 ) 计算
计算:b^(3n-1)/a^(2n-1)×c÷b^(3n-2)/a^2n
(3a^n-2)-6a^n+14a^n-1(因式分解) (m-n)^3+4(n-m)
分式计算:(b^3n-1 )*c/(a^2n+1)除以 (b^3n-2)/(a^2n)
a^(n+1)b^n-4a^(n+2)+3ab^n-12a^2
a(n+1)-3^(n+1)=-2(a(n)-3^n)怎么推出a(n)-3^n=2(-2)^(n-1)
计算:-2a^n(3a^(n+1)+4a-1)=