计算:(根号2/(1+i))^100+ (根号2/(1-i))^1000分
来源:学生作业帮 编辑:百度作业网作业帮 分类:数学作业 时间:2024/04/29 02:15:34
计算:(根号2/(1+i))^100+ (根号2/(1-i))^1000分
(根号2/(1+i))^100+ (根号2/(1-i))^100
(根号2/(1+i))^100+ (根号2/(1-i))^100
(1+i)^100
=[(1+i)²]^50
=(1+i²+2i)^50
=[(2i)²]^25
=-4^25
=-(2²)^25
=-2^50
(1-i)^100
=[(1-i)²]^50
=(1+i²-2i)^50
=[(-2i)²]^25
=-4^25
=-(2²)^25
=-2^50
(根号2/(1+i))^100+ (根号2/(1-i))^100
=2^50/(1+i)^100+ 2^50/(1-i)^100
=2^50/(-2^50) + 2^50/(-2^50)
=-1-1
=-2
=[(1+i)²]^50
=(1+i²+2i)^50
=[(2i)²]^25
=-4^25
=-(2²)^25
=-2^50
(1-i)^100
=[(1-i)²]^50
=(1+i²-2i)^50
=[(-2i)²]^25
=-4^25
=-(2²)^25
=-2^50
(根号2/(1+i))^100+ (根号2/(1-i))^100
=2^50/(1+i)^100+ 2^50/(1-i)^100
=2^50/(-2^50) + 2^50/(-2^50)
=-1-1
=-2
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