用换元法解方程:(xx−1
用换元法解方程:(xx−1
分式方程xx−1−1
(2003•武汉)用换元法解方程(xx−1)2−5(xx−1)+6=0时,设xx−1=y,则原方程化为关于y的方程是(
用换元法解方程2xx−1+x−1x=4
解方程:(1)2xx−2=1
解分式方程1−xx−2+2=12−x,可知方程( )
当k=______时,分式方程xx−1+kx−1−xx+1=0
解方程:2xx−2
关于x的方程xx−3
用换元法解分式方程2xx−1−5x−5x+3=0时,如果设xx−1=y,那么原方程可化为( )
解方程1/(xx+x)+1/(xx+3x+2)+1/(xx+5x+6)+1/(xx+7x+12)+1/(xx+9x+20
若关于x的方程2kx−1−xx