解方程:(x+1)(x²+x+1)-(x-1)(x²-x+1)=(4x+3)(x-2)
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解方程:(x+1)(x²+x+1)-(x-1)(x²-x+1)=(4x+3)(x-2)
快.
快.
(x+1)(x²+x+1)-(x-1)(x²-x+1)=(4x+3)(x-2)
(x+1)(x²-x+1+2x)-(x-1)(x²+x+1-2x)=(4x+3)(x-2)
(x+1)(x²-x+1)+2x(x+1)-(x-1)(x²+x+1)+2x(x-1)=(4x+3)(x-2)
x^3+1+2x(x+1)-(x^3-1)+2x(x-1)=(4x+3)(x-2)
x^3+1+2x(x+1)-x^3+1+2x(x-1)=(4x+3)(x-2)
2x(x+1)+2x(x-1)+2=(4x+3)(x-2)
2x(x+1+x-1)+2=(4x+3)(x-2)
4x^2+2=4x^2-5x-6
2=-5x-6
5x=-8
x=-8/5
(x+1)(x²-x+1+2x)-(x-1)(x²+x+1-2x)=(4x+3)(x-2)
(x+1)(x²-x+1)+2x(x+1)-(x-1)(x²+x+1)+2x(x-1)=(4x+3)(x-2)
x^3+1+2x(x+1)-(x^3-1)+2x(x-1)=(4x+3)(x-2)
x^3+1+2x(x+1)-x^3+1+2x(x-1)=(4x+3)(x-2)
2x(x+1)+2x(x-1)+2=(4x+3)(x-2)
2x(x+1+x-1)+2=(4x+3)(x-2)
4x^2+2=4x^2-5x-6
2=-5x-6
5x=-8
x=-8/5
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