百度作业网计算：√4÷（1、2）ˆ-1+（-1）ˆ2013×4ˆ0
来源：学生作业帮 编辑：百度作业网作业帮 分类：数学作业 时间：2024/06/13 04:00:08
计算：√4÷（1、2）ˆ-1+（-1）ˆ2013×4ˆ0
x²+3x-1＝0
化简求值（x-y）/(x²-2xy+y²)-(xy-y²)/(x²-y²),其中（x-2）²+∣y-3∣=0
x²+3x-1＝0
化简求值（x-y）/(x²-2xy+y²)-(xy-y²)/(x²-y²),其中（x-2）²+∣y-3∣=0
√4÷（1/2）ˆ-1+（-1）ˆ2013×4ˆ0
=2÷2 +(-1)×1
=1 -1
=0
x²+3x-1＝0
Δ=3²-4*1*(-1)=9+4=13
x=(-3±√13)/2
（x-y）/(x²-2xy+y²)-(xy-y²)/(x²-y²)
=(x-y)/(x-y)² - y(x-y)/[(x+y)(x-y)]
=1/(x-y) - y/(x+y)
已知（x-2）²+∣y-3∣=0,则有：
x-2=0且y-3=0
解得：x=2,y=3
所以所求式子=1/(x-y) - y/(x+y)=1/(2-3) - 3/(2+3)=-1 - 3/5=-8/5
=2÷2 +(-1)×1
=1 -1
=0
x²+3x-1＝0
Δ=3²-4*1*(-1)=9+4=13
x=(-3±√13)/2
（x-y）/(x²-2xy+y²)-(xy-y²)/(x²-y²)
=(x-y)/(x-y)² - y(x-y)/[(x+y)(x-y)]
=1/(x-y) - y/(x+y)
已知（x-2）²+∣y-3∣=0,则有：
x-2=0且y-3=0
解得：x=2,y=3
所以所求式子=1/(x-y) - y/(x+y)=1/(2-3) - 3/(2+3)=-1 - 3/5=-8/5