( )÷2xy=x²y-2xy²+1括号里应填?
( )÷2xy=x²y-2xy²+1括号里应填?
去括号:1/2(2X²Y-3XY²+4XY-X²Y²)=?
x-y/x²÷x²-2xy+y²/xy*(xy-x²)
已知(x+1)²+|y-1|=0,求2(xy-5xy²)-(3xy²-xy)得值
X²+2xy+y²/xy乘x²-2xy+y²/xy+y²=
化简求值:[(xy-2)²+4xy-4]÷(xy),其中x=10,y=1/25
因式分解xy²-2xy+x+2y-1
化简求值3x²y-[2xy-2(xy-3/2x²y)+xy]+3xy²其中x=3、y=-1
已知实数xy满足x²﹢y²-xy+2x-y+1=0求xy
先去括号,再合并同类项:3x²y-[2xy²-2(xy-2/3x²y)+xy]+3xy
请你先化简分式x²-2xy+y²/x²-xy÷(xy的-1次方-x的-1次方y),再将x=
(1)先化简,再求值:[4(xy-1)²-(xy+2)(2-xy)]÷1/4xy,其中x=-2,y=1/5.