lim(3-a(n-1))(6+an)=lim(3-an)(6+an) 是怎么变化过来的
lim(3-a(n-1))(6+an)=lim(3-an)(6+an) 是怎么变化过来的
若数列{an}满足a1=根号6 a(n+1)=根号下an+6 (n∈N*) 如果lim an 存在,求lim an的值[
数列极限的运算lim an/(an+1) =2 求lim 2anlim (2n+1)*an=3 求lim n*an
已知lim(3An+4Bn)=8,lim(6An-Bn)=1,求lim(3An+Bn)的值
已知lim(3an+4bn)=8,lim(6an-bn)=1,则lim(3an+bn)的值是多少
数列极限基本题已知数列{an}的极限为0,且有lim[(3n-2)an]=6,则lim[n(an)]=?
若数列an满足a1=√6,a(n+1)=√(an+6),如果lim(an)存在,求lim(an)
高二的极限运算题 lim(2an+4bn)=8,lim(6an-bn)=1,求lim(3an+bn)的值 n趋向于无穷大
极限的运算法则!已知 lim(2n+1)an=3,lim(nan)=
若数列{an}满足a1=√(6),an+1=√(an+6),(n∈N),如果lim(an)存在,求lim(an)
若lim[(2n-1)an]=1 求lim(n*an)的值
数列an的前n项的和Sn=(1/3)*an-2,求:lim(a1+a2+...+an)