tan(α+π/4)=2,则cos2α+3sin^2α+tan2α=?
tan(α+π/4)=2,则cos2α+3sin^2α+tan2α=?
已知tanα=3,α属于(π/4,π/2)求sin2α,cos2α,tan2α的值
已知tanα=1\2 求sin2α 、cos2α、tan2α的值.
tan(π/4+α)=2010,那么1/cos2α+tan2α=
已知sinα=1/3,α∈(π/2,π),求sin2α,cos2α,tan2α的值
已知(1+tan2α)/(1-tanα)=2010,求(1/cos2α)+tan2α
已知tan[α+π/4]=2,求cos2α+3sin²α的值
已知sinα=5/13,α∈(π/2,π)求sin2α,cos2α,tan2α的值
已知sinα=12/13,α∈(π/2,π)求sin2α,cos2α,tan2α的值
证明:tan(α+π/4)+tan(α+3π/4)=2tan2α
tan^2α=2tan^2 β+1则 cos2α+sin^2β等于?
α,β在第二象限,且sinα=1/3,cosβ=-½,求sin2α,cos2β,tan(α-β),tan2β,