cos*π/12—sin*π/12
cos*π/12—sin*π/12
sinπ/24*cosπ/24*sinπ/12=—— 答案是这么写的:1/2(2sinπ/24*cosπ/24)cosπ
计算cosπ/12*sinπ/12
求值:sin(π/12)+cos(π/12)
(cosπ/12-sinπ/12)*(COSπ/12+sinπ/12)等于
cos sin π √
已知α=7/12π,那么cosα√(1-sinα)/(1+sinα)+sinα√(1-cosα)/(1-cosα)=
根号3×cosπ/12-sinπ/12=?
高中数学题sinπ/12·cosπ/12
cos(π/12)^4+sin(π/12)^4=
求sin π/12-(根号3)cos π/12
cosπ/12+(根号3)×sinπ/12的值