cos(19π/6)+tan(16π/3)=?
cos(19π/6)+tan(16π/3)=?
sin(-21π/4) cos(-20π/3) tan(-19π/6)=
cos(6分之19π)tan(-3分之16π)
cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?.
已知tanα/2=2,1.求tan(α+π/4)的值 2.(6sinα+cosα)/(3sinα-2cosα)的值
已知tanα/2=2求tan(α+π/4)的值(6sinα+cosα)/(3sinα-2cosα)的值
若tanθ=根号3/3,则cos^2θ-sin(θ+π/6)cosθ的值
tan(a-4π)cos(π+a)sin^2(a+3π)/tan(3π+a)cos^2(2/5π+2)=0.5,求tan
【sin330°*tan(-13π/3)】/【cos(-19π/6)*cos690°】
[sin330°-tan(-13π/3)]/[cos(-19π/6)-cos690°]
sin(-4π/3)cos(-23π/6)tan(25π/4)=?
已知tan(π/6-α)=1/3 求cos(2α+2π/3)