求定积分下限为0,上限为π/2 ∫√(1-sin2x) dx=∫I sinx-cosx I dx=
求定积分下限为0,上限为π/2 ∫√(1-sin2x) dx=∫I sinx-cosx I dx=
求定积分上限为兀下限为0 x(sinx)^3/[1+(cosx)^2]dx
定积分∫(sinx)∧4(cosx)∧2dx(上限为π/2,下限为0)
求定积分∫上限为π/2下限为0 sin^3/(1+cosx)dx
定积分∫(下限0,上限π/2)(sinx)^6/((sinx)^6+(cosx)^6)dx=?
定积分∫上限π/2下限0 sinx/(sinx+cosx)dx
求定积分∫|sinx|dx(下限0,上限为2派)
求定积分下限∫-π/2到上限π/2sinx/(2+cosx)dx
求定积分∫(上限为π/2.下限为0)|1/2-sin x| dx
∫sin2x/[4+e^(sinx)^2]dx=?积分上限π/2,下限0
求定积分∫ 上限2arctan2,下限π/2,1/(1-COSx)sinx*sinx dx
定积分∫((sinx)^2+sin2x)|sinx|dx(上限9π/2,下限π/2)