计算sin10π-√2cos(-19π/4)-tan(-13π/3)=

cosπ/3－tanπ/4+cosπ－sin3π/2 化简计算 三角函数计算：若sinθ+cosθ=√2 则tan(θ+π/3)=? 已知tan(a-4/π)=2,计算1/(2sinacosa+cos^2a) 数学角度计算cos(π/3)-sin＾2(π/4)+1/3*tan＾2 (π/3)*sin(3π/2)+cosπ=?注： tan(a-4π)cos(π+a)sin^2(a+3π)/tan(3π+a)cos^2(2/5π+2)=0.5,求tan 已知sin a=2cos a 计算⑴（sinα+2cosα)/(5cosα-sinα) ⑵tan(α+π/4) 计算sin(-α-5π)*cos(α-2分之π)-tan(α-2分之3π)*tan(2π-α) cos(19π/6)+tan(16π/3)=? 已知sin(π+α)=-1/2 计算 cos(2π-α) tan(α-7π) cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?. 已知cos(π+α)=-1/2 计算sin(2π+α)-tan(α-3π)的值 化简：[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(