当x→0时,lim[ln(1+2x)+xf(x)]/x^2=2,求lim[2+f(x)]/x 要求详细解释

当x→0时,lim[ln(1+2x)+xf(x)]/x^2=2,求lim[2+f(x)]/x 要求详细解释 当x→0时,lim[ln(1+2x)+xf(x)]/x^2=2,求lim[2+f(x)]/x 当x→0时,lim[ln(1-2x)+xf(x)]/x^2=4,求lim[f(x-2)]/x lim(e^2x-1)/ln(1+x),求当x→0时的极限 已知x-->0时,lim{ln[1+f(x)/tanx]/(3^x-1)}=2,求lim(x-->0)[f(x)/x^2 已知lim x→0 [sin6x+xf(x)]/x^3=0,求 lim x→0 [6+f(x)]/x^2? lim x→0 [sin6x+xf(x)]/x^3=0,求 lim x→0 [6+f(x)]/x^2 设x->0时,lim((sin6x+xf(x))/x^3)=0,求x->0时,lim((6+f(x))/x^2). 求lim（x→0）[(xf'(x))/(2f(x))]^(1/x),其中f(x)在x=0点某邻域内有三阶连续导数,f(0 设f(x)在x=0的某邻域内连续,且lim x→0 [xf(x)-ln(1+x)]/x^2=2,求f(0),并证明f`（ lim(x→0)ln(1-2x)/x f(x)在x=0的领域内有二阶导数,又x→0时lim((sinx+xf(x))\x3)=1/2,求f(0),f'(0),