如果xy=sinx * cosy,求dy/dx
如果xy=sinx * cosy,求dy/dx
求方程(xy+y+sinx)dx+(x+cosy)dy=0的通解
(cosy)^x=(sinx)^y求dy/dx
xy+cosy-sinx=1,求dy.
sinx+ siny=xy求dy/dx
(cosy+ycosx)dx+(sinx-siny)dy=0
e^x=cosy-xy^2,求dy/dx|x=0
(sinx)^cosy=(cosx)^siny,求dy?(^代表幂)
微分方程(1+y^2)dx+(xy-genhao1+y^2 cosy)dy=0
(1+y^2)dx+(xy-根号下(1+y^2 ) cosy)dy=0
y=(sinx)^x 求DY/DX
y=ln sinx,求Dy/Dx