AD平行BC,角ABC=角DCB,AB=DC,AE=DF,连接BF,CE求证BF=CE
AD平行BC,角ABC=角DCB,AB=DC,AE=DF,连接BF,CE求证BF=CE
在四边形ABCD中,AD‖BC,角ABC=角DCB,AB=DC,AE=DF.求证:BF=CE
如图①所示,已知四边形ABCD中,AD//BC,∠ABC=∠DCB,AB=DC,AE=DF,试说明BF=CE
在四边形ABCD中,AD∥BC,∠ABC=∠DCB,AB=DC,AE=DF,证明:BF=CE
已知如图(1)在四边形ABCD,AD‖BC,∠ABC=∠DCB.AB=CD,AE=DF,求证BF=CE
已知:如图,AD=CD CE=BF DF=AE 求证AB‖DC
在四边形ABCD中,AD//BC,∠ABC=∠DCB,AB=DC,AE=DF.(1)求证BF=CE(2)当E、F相向运动
如图,在梯形ABCD中,AB//CD,AD=BC,点E,F在AB上,且AE=BF,连接CE,DF.求证:CE=DF .
AB=CD,AE垂直BC,DF垂直BC,CE=BF,求证AE=DF
如图,AB=CD,AE=DF,CE=BF,求证AE平行DF
如图,AB=CD,AE=DF,CE=BF,求证:AE平行DF
如图所示,E,F为AD边上的两点,且AE=DF,AB=DC,BE=CF.求证:BF=CE.BF∥CE.