数列{An}{Bn}满足下列条件：A1=0,A2=1,An+2=An+An+1/2,Bn=An+1-An

数列{An}{Bn}满足下列条件：A1=0,A2=1,An+2=An+An+1/2,Bn=An+1-An 数列{an}和{bn}满足a1=1 a2=2 an>0 bn=根号an*an+1 已知数列{an}满足a1=1,a2=2,an+2=(an+an+1)/2,n∈N*.令bn=an+1-an,证明{bn} 数列{an}和{bn}满足a1=1 a2=2 an>0 bn=根号an*an+1且{bn}是以公比为q的等比数列 数列an中,a1=3,an=(3an-1-2)/an-1,数列bn满足bn=an-2/1-an,证明bn是等比数列 2. 数列an满足a1+a2+a3+...+an=n^2,若bn=1/an(an+1),求bn的和sn 在数列{an}中,a1=-1,a2=0,an+1+4an-1=4an（n≥2）,数列｛bn｝满足bn=an+1-2an. 已知数列{an}满足:a1+a2+a3+…+an=n-an 求证{an-1}为等比数列 令bn=(2-n)(an-1)求 已知数列{an}、{bn}满足:a1=1/4,an+bn=1,bn+1=bn/1-an^2 （1）求{an}的通项公式 已知数列{an}满足a1=1,a2=a（a>0）,数列{bn}=an*an+ 数列{an} {bn}满足：a1=0 a2=1 a(n+2)=[an+a(n+1)]/2 bn=a(n+1)-an 求证 数列{an}中,a1=1,a2=2,数列{bn}满足bn=an+1+[(-1)^n]an,n属于N*.