函数f(x)=2cosxsin(x+π/3)-根号3sin^2x+sinxcosx的最小值为多少?此时x等于多少
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函数f(x)=2cosxsin(x+π/3)-根号3sin^2x+sinxcosx的最小值为多少?此时x等于多少
![函数f(x)=2cosxsin(x+π/3)-根号3sin^2x+sinxcosx的最小值为多少?此时x等于多少](/uploads/image/z/7458126-6-6.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%3D2cosxsin%28x%2B%CF%80%2F3%29-%E6%A0%B9%E5%8F%B73sin%5E2x%2Bsinxcosx%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E4%B8%BA%E5%A4%9A%E5%B0%91%3F%E6%AD%A4%E6%97%B6x%E7%AD%89%E4%BA%8E%E5%A4%9A%E5%B0%91)
f(x)=2cosxsin(x+π/3)-√3sin^2x+sinxcosx
=2cosx(√3/2sinx+1/2cosx)-√3sin^2x+1/2sin2x
=√3/2sin2x+cos^2x-√3sin^2x+1/2sin2x
=(√3+1)/2sin2x+cos^2x-√3sin^2x
=(√3+1)/2sin2x+(cos2x+1)/2+√3/2(cos2x-1)
=(√3+1)/2(sin2x+cos2x)+(√3-1)/2
=(√6+√2)/2sin(2x+π/4)+(√3-1)/2
2x+π/4=2kπ-π/2 , x=kπ-3π/8 , k∈Z
最小值f(kπ-3π/8)=-(√6+√2)/2+(√3-1)/2
=2cosx(√3/2sinx+1/2cosx)-√3sin^2x+1/2sin2x
=√3/2sin2x+cos^2x-√3sin^2x+1/2sin2x
=(√3+1)/2sin2x+cos^2x-√3sin^2x
=(√3+1)/2sin2x+(cos2x+1)/2+√3/2(cos2x-1)
=(√3+1)/2(sin2x+cos2x)+(√3-1)/2
=(√6+√2)/2sin(2x+π/4)+(√3-1)/2
2x+π/4=2kπ-π/2 , x=kπ-3π/8 , k∈Z
最小值f(kπ-3π/8)=-(√6+√2)/2+(√3-1)/2
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