(a^2+b^2)(a^2+b^2-1)-56=0,a^2+b^2=?
{1,a,b/a}={0,a^2,a+b}
A=B+B+B+B+B+B+B+B+B+B+B+B+B+B+B A-B×3=C C+2×7+2=1
a-b\a+b=1\2时,求代数式a+b\3(a-b) - a-b\2(a+b)
已知2a-b+1的绝对值+(3a+3/2b)^=0,求(b^/a+b)÷{[(b/a-b)+1][a-(a^/a+b)]
化简求值(a-b)/(a+b)+(a+b)/(a-b)-(2a*a-2b*b)/(a*a+b*b)其中a=-2,b=0.
已知|2a-b+1|+(3a+3/2b)^2=0求b^2/a+b/{(a/a-b-1)(a-a^2/a+b)}
已知|2a-b+1|+(3a+3/2b)^2=0求[b^2/a+b]/[(a/a-b-1)][(a-a^2/a-b)}
若a/b=2 则a*a-ab+b*b/a*a+b*b等于?
a(a-2b)+2(a+b)(a-b)+(a+b)²,其中a=-½,b=1
a(a-1)-(a×a-b)=-5,求(a×a+b×b)÷2-ab
(2a+b)(a-b)=8 求a,b
若2/a-2/b=1/(a-b),则b/a+a/b=?